Calculates the component values to make a passive 'lumped' or 'all in one' RIAA replay equalisation network of my type RIAA-1 as shown in this pdf and below ~ With R1 connected parallel to C1 the 4 terminal network can be used as a 2 terminal type which develops a voltage across it or current through it depending how it is driven and terminated
Correct equalisation using this 4 terminal network is only obtained with 0Ω source and ∞Ω load so 'perfect' amplifiers are required either side of the networks but they can incorporate a resistive source Rs if R1 is reduced by Rs ~ A resistive load RL will appear in parallel with R1 so the value (R1–Rs) can then be increased to accommodate RL
Thus a single adjustment of R1 for this network can correct for both Rs and RL and is often required in practice where amplifiers have significant output and/or input impedance ~ It is also possible that the impedances of amplifiers either side of the 4 terminal network are such that R1 does not need to be changed
The 2 terminal or current driven networks are often used in negative feedback loops and have been for many years before transistors and op-amps ~ When driven from a 'lowish' output impedance and terminated into a low resistance feedback node the Current through the network has the RIAA Record characteristic the inverse of RIAA playback
The rising current with with frequency develops a voltage across R! which could be a cathode or emitter resistor or part of an op–amp feedback loop and reduces the gain of the amplifier in accordance with RIAA playback EQ ~ Depending on the quality of the amplifier and the feedback topology used you may get acceptable playback of vinyl records
I refer to the 2 terminal networks as 'current driven' because that is how I often use them as the load on the output of a Transconductance amplifier which could be the collector of a transistor with un–bypassed emitter resistor or the anode circuit of a Cascode or Pentode where the current develops the output voltage across the network wrt signal ground which may be the HT supply As shown here ΐ